用Shell脚本获取CPU拓扑关系

准确说这不是一个问题，因为地球人都知道cat /proc/cpuinfo获取CPU信息。但是，你能从那一大片输出里面立马看出来是多个物理CPU呢，还是多核呢，还是超线程之类的东东么？

        本文给出一个脚本，通过分析proc来给出一个清晰的答案，本人写的脚本通用性可能比较差，大家根据情况进行修改，基本上在偶这里没啥问题。

先说点基础：
/proc/cpuinfo里面：
processor表示逻辑CPU号（核或线程）
core id表示CPU核号
physical id表示物理CPU号

脚本如下：

cpu_p=`cat /proc/cpuinfo | grep "physical id" | sort | uniq | wc -l` cpu_c=`cat /proc/cpuinfo | grep "core id" | uniq | wc -l` cpu_l=`cat /proc/cpuinfo | grep "processor" | wc -l` c_p=`expr $cpu_c / $cpu_p` l_p=`expr $cpu_l / $cpu_p` t_c=`expr $cpu_l / $cpu_c` echo "Physical CPU Count: $cpu_p" echo "CPU Core Count   : $cpu_c" echo "Logical CPU Count: $cpu_l" echo "$c_p cores per physical CPU" echo "$l_p logical CPUs per physical CPU" echo "$t_c threads per core" if [ $c_p -eq 1 ]; then   echo "Your CPU is unicore" else   echo "Your CPU is multicore" fi if [ $t_c -eq 1 ]; then   echo "Your CPU isn\'t of HT" else   echo "Your CPU is of HT" fi echo "You have $cpu_p CPUs, each CPU has $c_p cores, each core has $t_c threads. In summary $cpu_c cores, $cpu_l threads."

下面是在俺这里的运行结果：
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